Ek ghane jungle mein aap akele…raat ke 2 baje ka time.....Ek ghane jungle mein aap akele…raat ke 2 baje ka time.....Zoron se hawa chalti hui..Samne ped par ek laash latki hui…jiski ankhen bahar lataki hui.Apke dil men ghabrahat, sanse tej chalti hui.Aap us laash ke paas gaye…..achanak ped ki tehni tuti aur laash aap ke upar giri..Then..Calculate the force with which the body will fall on you.Also calculate the kinetic energy when the body will be at height 6 ft from ground?(Take g=9.8m/sec sqre, mass=66 kg).
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Given:-
Mass of a laash m = 66 kg
Acceleration due to gravity g = 9.8 m/s²
≈ 10 m/s
Height h = 6 ft
1 foot = 0.305 m
6 ft = 6 * 0.305
= 1.83 m
≈ 1.9 m
Calculation:-
i) The force with which the body will fall on you.
Force of gravity = Mass * Acceleration due to gravity
F = mg
F = 66 * 10
F = 660 kgm/s²
F = 660 N Ans.
Ans.) The body will fall on you with the force of 660 N.
ii) The kinetic energy when the body will be at height 6 ft from ground.
v² - u² = 2gh (Third equation of motion due to gravity)
v² - (0)² = 2 * 10 * 1.9
v² = 2 * 19
v² = 38
Kinetic energy = 1/2 * Mass * Velocity²
Ek = 1/2 * m * v²
Ek = 1/2 * 66 * 38
Ek = 66 * 19
Ek = 1254 J Ans.
Ans.) The kinetic energy when the body will be at height 6 ft from ground would be 1254 J.
Mass of a laash m = 66 kg
Acceleration due to gravity g = 9.8 m/s²
≈ 10 m/s
Height h = 6 ft
1 foot = 0.305 m
6 ft = 6 * 0.305
= 1.83 m
≈ 1.9 m
Calculation:-
i) The force with which the body will fall on you.
Force of gravity = Mass * Acceleration due to gravity
F = mg
F = 66 * 10
F = 660 kgm/s²
F = 660 N Ans.
Ans.) The body will fall on you with the force of 660 N.
ii) The kinetic energy when the body will be at height 6 ft from ground.
v² - u² = 2gh (Third equation of motion due to gravity)
v² - (0)² = 2 * 10 * 1.9
v² = 2 * 19
v² = 38
Kinetic energy = 1/2 * Mass * Velocity²
Ek = 1/2 * m * v²
Ek = 1/2 * 66 * 38
Ek = 66 * 19
Ek = 1254 J Ans.
Ans.) The kinetic energy when the body will be at height 6 ft from ground would be 1254 J.
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