Question

ek isosceles triangle ki barabar bhujayen 18m ho
तो उसका क्या होगा?​

Answer 1

Answer:

Appolonius Theorem.

$Appolonius Theorem.</p><p></p><p>cosA=b2+c2−a22bc⟹cosA=2b2−a22b2⟹sinA=1−(2b2−a22b2)2−−−−−−−−−−−−−−√⟹sinA=(2b2)2−(2b2−a2)2−−−−−−−−−−−−−−−−√2b2⟹sinA=a2(4b2−a2)−−−−−−−−−−√2b2⟹sinA=a4b2−a2−−−−−−−√2b2cos⁡A=b2+c2−a22bc⟹cos⁡A=2b2−a22b2⟹sin⁡A=1−(2b2−a22b2)2⟹sin⁡A=(2b2)2−(2b2−a2)22b2⟹sin⁡A=a2(4b2−a2)2b2⟹sin⁡A=a4b2−a22b2</p><p></p><p>Δ=12bcsinA⟹Δ=12b2⋅a2b24b2−a2−−−−−−−√⟹Δ=14a4b2−a2−−−−−−−√⟹a2(4b2−a2)=16Δ2⟹4a2b2−a4=16Δ2⟹a4−4a2b2+16Δ2=0⟹a2=4b2±(4b2)2−4(16Δ2)−−−−−−−−−−−−−√2⟹a2=4b2±4b4−4Δ2−−−−−−−√2⟹a2=2b2±2b4−4Δ2−−−−−−−√⟹a=2b2±2b4−4Δ2−−−−−−−√−−−−−−−−−−−−−−−√The solution will be the value of b for which b4−4Δ2≥0Δ=12bcsin⁡A⟹Δ=12b2⋅a2b24b2−a2⟹Δ=14a4b2−a2⟹a2(4b2−a2)=16Δ2⟹4a2b2−a4=16Δ2⟹a4−4a2b2+16Δ2=0⟹a2=4b2±(4b2)2−4(16Δ2)2⟹a2=4b2±4b4−4Δ22⟹a2=2b2±2b4−4Δ2⟹a=2b2±2b4−4Δ2The solution will be the value of b for which b4−4Δ2≥0</p><p></p><p>$

hope it helps thankx ohk