Question

ek khambhe ki 2/5bhag kichad me and sesh 1/3bhag pani me and 6 meter water k upper me to pole ki height
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$let \: the \: height \: be \: x \\ kichad \: ka \: bhag = \frac{2}{5} x \\ pani \: ka \: bhag = \frac{2}{5} x \times \frac{1}{3} = \frac{2}{15} x$

A/Q

$x - \frac{2}{15} x = 6 \\ \frac{15x - 2x}{15} = 6 \\ \frac{13x}{15} = 6 \\ x = 6 \times \frac{15}{13} = \frac{80}{13}$