Question

Ek railgadi Ek Saman chaal se 360 kilometre ki Duri Tay Karti Hai yadi chaal 5 kilometre Prati Ghanta Adhik hoti hai to see Yatra mein ek ghanta kam Samay Leti Hai railgadi ki Chaal gyat kare​

Answer 1

(360/x)-(360/(x+5))=1

(360(x+5)-360x)/x(x+5)=1

360x+1800-360x=x (x+5)

x(x+5)=1800

x(x+5)-1800=0

x=40kmph

Answer 2

Solution :-

Given : Distance = 360 km

Let the speed of train be x km/hr

Time = 360/x hours

According to the question,

=> (x + 5) (360/x - 1) = 360

=> (x + 5) {(360 - x)/x} = 360

=> (x + 5) (360 - x) = 360x

=> 360x - x² + 1800 - 5x = 360x

=> x² + 5x - 1800 = 0

=> x² + 45x - 40x - 1800 = 0

=> x(x + 45) - 40(x + 45) = 0

=> (x - 40) (x + 45) = 0

=> x = 40 or x = - 45

∴ x = 40 (Because speed is taken positive)

Hence,

Speed of train = 40 km/hr