ek sankhya batao Jo 100 se aadhe hai 40 se jyada per 50 se kam hai jismein dahi ka ank ikai ke ank se 2 adhik hai is anko ka jod 6 hai
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Given :-
- Number is less than half of 100 .
- Greater than 40 .
- Tens digit is 2 greater than the unit's digit .
- Sum of digits is 6.
Solution :-
Let us assume that, the required number is (10x + y) .
→ Less than = 100/2 = Less than 50 and greater than 40 .
so,
→ 40 < 10x + y < 50 .
now,
→ x + y = 6
→ x - y = 2
2x = 8
→ x = 4 .
then,
→ y = 6 - 4 = 2 .
therefore,
→ Required number = 10x + y = 10*4 + 2 = 40 + 2 = 42 (Ans.)
Learn more :-
State a number which is less than half of 100,less than 50 but more than 40,in which the tens digit is 2 more than the u...
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