Math, asked by dheeraj1438, 1 year ago

ek shankhya ko 342 se bhai dene par sashphal47 at a hai agar god shankhya ko 19 se bhag de to sesh kya hoga

Answers

Answered by adee1729

1

A=342×q+47,. A=342×q+19×2+9,. A=(342×q+38)+9,,,, since here 9 is remaining then 9 will be the remainder

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