Ek snkhya me do ank h dhai k sthan ka ank ikai k sthan k and we 2 adhik h .anko ka you 1/6 h to snkhya h
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Let the unit digit number is x
Tens digit number is y
The number is of the for 10 y + x
It is given number in the tens place = 3 times the number in the unit place
Therefore y = 3 x
The reversed number is 10 x + y
10 y + x + 10 x + y = 88
11 x + 11 y = 88 [dividing both sides by 11]
x + y = 8
x + 3 x = 8 [ since y= 3 x]
4 x = 8
x = 2
y = 3 x = 6
The two digit number is 10(6) + 2 = 62
Reversed number = 26
Verification Number in the tens place = 3 x number in the unit place
6 = 3(2)
sum of the number and the reversed = 88
62 + 26 = 88
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