Question

ek solution me mass ke anusar 25% water 25% athil alcohol and 50%asitik acid hai solution me sabhi Ghatak ke mole fraction Ko gyat kijiye​

Answer 1

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Answer 2

Answer:

Let the mass of solution is 100g

Then, mass of H

2O=25g

mass of ethanol =25g

mass of acetic acid =50g

Number of moles of water = 18g/mol

25g =1.4

Number of moles of ethanol = 46g/mol

25g=0.54

Number of moles of Acetic acid = 60g/mol

50g=0.8

Total number of moles =(1.4+0.54+0.8)=2.74

Now, mole fraction of water = 2.741.4=0.51

mole fraction of Ethanol = 2.740.54=0.197

mole fraction of acetic acid = 2.740.8 =0.291

I hope it's helpful for you Neha