Question

ek train 90 km/hr se travel karta hai break apply karne ke baad -.5 m/s square accellaration produce karta hai to kitna distance travel karne ke baad train stop hota hai​

Answer 1

Explanation:

$given \: \: \: speed \: = 90km| hr \\ time \: = - 5m| sec \\convert \: 90km| hr \: into \: m| sec \\ 90 \times \frac{18}{5} \\ 18 \times 18 = 324m| sec \\ speed \: = \frac{distance}{time \: taken} \\ \\ 324m| sec = \frac{distance}{ - 5m|sec } \\ distance = 324m|sec \times - 5m|sec \\ distance \: = - 1620m| sec {}^{2}$

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