एक 6 सेमी का रेखाखंड AB ख5िचए। लर और परकार क) सहायता से उसका लंब समि7भाजक ख5िचए
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Answered by
1
Answer:
The length is 9 cm and width is 6 cm.
Step-by-step explanation:
Given:
Length of a rectangle is 3 more than its Width.
Perimeter of the rectangle is 30 cm
To find:
The length and width of the rectangle
Solution:
Let,
Width = x
Length = x + 3
Perimeter of the rectangle is 30 cm
Perimeter = 2 (Length + Width)
\longrightarrow⟶ 30 = 2 [(x + 3) + x]
\longrightarrow⟶ 30 = 2x + 6 + 2x
\longrightarrow⟶ 30 = 4x + 6
\longrightarrow⟶ 30 - 6 = 4x
\longrightarrow⟶ 4x = 24
\longrightarrow⟶ x = 24/4
\longrightarrow⟶ x = 6
Width = 6 cm
★ Length = x + 3
\longrightarrow⟶ 6 + 3
\longrightarrow⟶ 9
Length = 9 cm
Therefore, the length is 9 cm and width is 6 cm.
Answered by
0
Answer:
6 CM ka Rekha Khand kijiye rula aur prakar ki sahayata se uska lamberson deba jid dijiye
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