Question

एका अंकागणिती d=10 तर t6-t2 काढा

Answer 1

d = 10

Tn = a + (n-1)d

T6 = a + (6-1)10 = a + 5×10 = a + 50

T2 = a + (2-1)d = a + d = a + 10

T6 - T2 = a+50 - (a+10) = a+ 50 - a -10

= 40