एक आयत ABCD के विकर्ण पर पर्टिचेड करते है यदि Cod=78° hai Tho OAB hoga
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Solution :-
given that,
- ABCD is a rectangle .
- Diagonal AC and BD intersect at 0 .
- ∠COD = 78°
so,
→ ∠COD = ∠AOB { Vertically opposite angles. }
→ ∠AOB = 78°
now, in ∆AOB we have,
→ ∠AOB = 78°
→ OA = OB { Diagonals of a rectangle bisect each other equally. => OA = OB = OC = OD . }
then,
→ ∠OAB = ∠OBA { Angle opposite to equal sides are equal in measure. }
therefore,
→ ∠AOB + ∠OAB + ∠OBA = 180° { By angle sum property. }
→ 78° + 2•∠OAB = 180°
→ 2•∠OAB = 180° - 78°
→ 2•∠OAB = 102°
→ ∠OAB = 51° (Ans.)
Learn more :-
In ABC, AD is angle bisector,
angle BAC = 111 and AB+BD=AC find the value of angle ACB=?
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