Question

एक आयत की परिधि 52 सेमी है। यदि इसकी चौड़ाई आयत की लंबाई और चौड़ाई से 2 सेमी अधिक है​

Answer 1

Answer:

let the breadth of rectangle=x cm

length=x+2 cm

perimeter of rectangle=2(l+b)

52=2(x+2+x)

52=2(2x+2)

52/2=2x+2

26=2x+2

2x=26-2

2x=24

x=24/2=12

x=12

breadth=12cm

length=12+2=14cm

Answer 2

Answer:

Breadth of rectangle = x cm = 12 cm

Length of rectangle = (x+2) cm = 14cm

Step-by-step explanation:

Given:

Perimeter of rectangle = 52 cm

Let the length and breadth of a rectangle be l and b respectively.

Let the bradth if rectangle be x cm

Then,

The length of rectangle be (x + 2 ) cm

According to the question

Perimeter of rectangle = 52 cm

2 (l + b) = 52 cm

2(x + x + 2) = 52 cm

2 (2x + 2) = 52 cm

2x + 2 = 52/2 cm

2x + 2 = 26 cm

2x = (26 -2) cm

2x = 24cm

x = 24/2 cm

x = 12 cm

(x + 2) cm = (12 + 2) cm = 14 cm

Breadth of rectangle = x cm = 12 cm

Length of rectangle = (x+2) cm = 14cm