Physics, asked by neetuagarwal45678, 10 months ago

एक्चुअली अचानक तल पर 2ms - 2 के तोरण से नीचे जा रही है गति प्रारंभ करने के 3 सेकंड के पश्चात का वेग क्या होगा

Answers

Answered by suneelky9125

0

Answer:

v = u +a×t

u=0

v=a×t= 2×3 =6

Answered by rajeshjain10

0

Answer:

can you write in English

so I can help

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