Math, asked by safeen4372, 5 months ago

एक डिब्बे में छ: नारंगी।
बाँटो ऐसे छ: बच्चों में
इक नारंगी बच भी जाए
उस नारंगी के डिब्बे में।
बिन काटे हम बाँटें कैसे,
साबुत सब पा जाएँ जैसे

Six oranges in a box.
Divide into six children
Even an orange survives
In that orange box.
How do we share without cutting
Get everything like​

Answers

Answered by khushpreet50
11

Step-by-step explanation:

In the first experiment:-

Weight of copper oxide, (CuO)=1.288g

Weight of copper =1.03g

Weight of oxygen = Wt. of copper oxide − Wt. of copper =1.288−1.03=0.258g

Wt. of oxygen

Wt. of copper

=

0.258

1.03

1

4

In the second expriment:-

Weight of copper oxide (CuO)=3.672g

Weight of copper =2.938g

Weight of oxygen = Wt. of copper oxide − Wt. of copper =3.672−2.938=0.734g

Wt. of oxygen

Wt. of copper

=

0.734

2.938

1

4

The proportion of elements of copper and oxygen in the reactions is same.

Hence law of constant proportion is proved.

Answered by thequeen45
1

Give the box with the last orange

or

To have one orange in basket , we have to give orange with basket to one of the girl

Step-by-step explanation:

There are 6 oranges in a basket.

We have to divide 6 oranges among six girls

Each girls gets an orange

So total orange required = number of girls * one girls get orange

= 6 * 1

= 6

We have total 6 oranges

so we are not left with any ornage

To have one orange in basket , we have to give orange with basket to one of the girl

hope helps plz adjust with example of girl

mark brainlist ☺️☺️

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