एक डिब्बे में छ: नारंगी।
बाँटो ऐसे छ: बच्चों में
इक नारंगी बच भी जाए
उस नारंगी के डिब्बे में।
बिन काटे हम बाँटें कैसे,
साबुत सब पा जाएँ जैसे
Six oranges in a box.
Divide into six children
Even an orange survives
In that orange box.
How do we share without cutting
Get everything like
Answers
Step-by-step explanation:
In the first experiment:-
Weight of copper oxide, (CuO)=1.288g
Weight of copper =1.03g
Weight of oxygen = Wt. of copper oxide − Wt. of copper =1.288−1.03=0.258g
∴
Wt. of oxygen
Wt. of copper
=
0.258
1.03
≈
1
4
In the second expriment:-
Weight of copper oxide (CuO)=3.672g
Weight of copper =2.938g
Weight of oxygen = Wt. of copper oxide − Wt. of copper =3.672−2.938=0.734g
∴
Wt. of oxygen
Wt. of copper
=
0.734
2.938
≈
1
4
The proportion of elements of copper and oxygen in the reactions is same.
Hence law of constant proportion is proved.
Give the box with the last orange
or
To have one orange in basket , we have to give orange with basket to one of the girl
Step-by-step explanation:
There are 6 oranges in a basket.
We have to divide 6 oranges among six girls
Each girls gets an orange
So total orange required = number of girls * one girls get orange
= 6 * 1
= 6
We have total 6 oranges
so we are not left with any ornage
To have one orange in basket , we have to give orange with basket to one of the girl