Question

एक गाड़ी के पहिये के घेरे 81 सेमी और 108 सेमी हैं। वह कौन-
सी सबसे कम दूरी है, जिसमें दोनों पहिये पूरे चक्कर लगायेंगे?
अंकगणित
(1)4:
(3) A
रेपी (2) 324 सेमी
(20
0​

Answer 1

Given:

एक गाड़ी के पहिये के घेरे 81 सेमी और 108 सेमी हैं। वह कौन-सी सबसे कम दूरी है, जिसमें दोनों पहिये पूरे चक्कर लगायेंगे?

The circumference of a carriage wheel are 81 cm and 108 cm. Which is the lowest distance in which the two wheels will rotate round? 1) 328 cm (2) 324 cm (3) 224 cm (4) 424 cm

To find:

वह कौन- सी सबसे कम दूरी है, जिसमें दोनों पहिये पूरे चक्कर लगायेंगे?

Solution:

The circumference of 1st carriage wheel = 88 cm

The circumference of the 2nd carriage wheel = 108 cm

To find the lowest distance that the two wheels should cover so that each wheel makes a complete number of rotations, we will have to calculate the L.C.M. of the circumference of the two wheels i.e., 81 cm and 108 cm.

Now, we will calculate the L.C.M. of 81 and 108 by using the prime factorisation method,

Factors of 81 and 108:

81 = 3 × 3 × 3 × 3

108 = 2 × 2 × 3 × 3 × 3

L.C.M. :

∴ L.C.M. of 81 and 108 = 2 × 2 × 3 × 3 × 3 × 3 = 2² × 3⁴ = 324 ← option (2)

Thus, the lowest distance in which the two wheels will rotate round is → 324 cm.

------------------------------------------------------------------------------------------------

Also View:

The circumference of the four wheels are 50 cm, 60 cm, 75cm and 100 cm. they start moving simultaneously what is the least distance they should cover so that each wheel makes a complete number of revolutions.

brainly.in/question/3037040

Answer 2

Answer:

324 laure. smjge 13567943556fdji repo Jaiswal