Math, asked by raj972112963, 2 months ago

एक ईमानदार व्यक्ति नेहा सच्चाई का मान कभी नहीं छोड़ता है​

Answers

Answered by almeidapetrick004
1

The given sequence is an A.P. with first term a=8−6i and common difference d=−1+2i. The nth term of the given A.P. is given by :

a  

n

​  

=a+(n−1)d=8−6i+(n−1)(−1+2i)=(9−n)+i(2n−8)

Let the nth term of the sequence is purely real.

Therefore,

(9−n)+i(2n−8) is purely real.

2n−8=0

n=4

So, 4th term of the sequence is purely real.

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