एका क्रमिकेचे n वे पद tn=2n-5 असेल तर तिची पहिली पाच पदे काढा
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Given : एका क्रमिकेचे n वे पद tₙ=2n-5
nth term of a sequence is tₙ=2n-5
To Find : पहिली पाच पदे काढा
Find first five terms.
Solution:
tₙ=2n-5
substitute n = 1 to find 1st term.
t₁ = 2(1) - 5 = - 3
substitute n = 2 to find 2nd term.
t₁ = 2(2) - 5 = - 1
substitute n = 3 to find 3rd term.
t₁ = 2(3) - 5 = 1
substitute n = 4to find 4th term.
t₁ = 2(4) - 5 = 3
substitute n = 5 to find 5th term.
t₁ = 2(5) - 5 = 5
पहिली पाच पदे
first 5 terms are :
-3 , - 1 , 1 , 3 , 5
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