Math, asked by Anonymous, 4 months ago

एक कमरा 12 मी. लम्बा, 9 मी. चौड़ा तथा 8 मी. ऊँचा है।
इसमें अधिकतम किस लम्बाई का बाँस रखा जा सकता है ?

Answers

Answered by 00200
1

Answer:

The parts of the cell that are organized for specific functions are called organelles. The organelles include such structures as the nucleus and the mitochondria. The nucleus contains the genetic material and the mitochondria convert energy. ... Each of these organelles has a special role to play in the way the cell works.23-Feb-2012

Answered by Anonymous
0

Answer:

\orange{\bold{\underbrace{\overbrace{❥Answer᎓}}}}

Integrate the function

\huge\green\tt\frac{ \sqrt{tanx} }{sinxcosx}}

\huge\tt\frac{ \sqrt{tanx} }{sinxcosx}

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\huge\tt \frac{ \sqrt{tanx} }{sinxcosx \times \frac{cosx}{cosx}}

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\huge\tt \frac{ \sqrt{tanx} }{sinx \times \frac{ {cos}^{2} x}{cosx}} ㅤ ㅤ ㅤ

\huge\tt\frac{ \sqrt{tanx} }{ {cos}^{2} x \times \frac{sinx}{cosx} }

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\huge\tt\frac{ \sqrt{tanx} }{ {cos}^{2}x \times tanx }

\huge\tt {tan}^{ \frac{1}{2} - 1 } \times \frac{1}{ {cos}^{2} x}ㅤ ㅤ ㅤ ㅤ ㅤ

\huge\tt {(tan)}^{ - \frac{ 1}{2} } \times \frac{1}{ {cos}^{2}x } = {(tanx)}^{ - \frac{1}{2} } \times {sec}^{2} x⇛(tan)

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\huge\tt {(tan)}^{ - \frac{ 1}{2} } \times \frac{1}{ {cos}^{2}x } = ∫ {(tanx)}^{ - \frac{1}{2} } \times {sec}^{2} x \times dx⇛(tan)

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\bold\blue{☛\: Let tanx=t}

\bold\blue{☛ \:Differentiating \: both \: sides \: w.r.t.x}

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\huge\tt {sec}^{2} x = \frac{dt}{dx}

\huge\tt{dx \frac{dt}{ {sec}^{2}x }}

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\huge\tt∴∫ {(tanx)}^{ - \frac{1}{2} } \times {sec}^{2} x \times dx

\huge\tt ∫ {(t)}^{ - \frac{1}{2} } \times {sec}^{2} x \times \frac{dt}{ {sec}^{2}x }

\huge\tt ∫ {t}^{ - \frac{1}{2} }ㅤ ㅤ

\huge\tt\frac{ {t}^{ - \frac{1}{2} + 1} }{ - \frac{1}{2} + 1 }

\huge\tt \frac{ {t}^{ \frac{1}{2} } }{ \frac{1}{2} } + c = 2 {t}^{ \frac{1}{2} } + c = 2 \sqrt{t}

\huge2 \sqrt{t} + c = 2 \sqrt{tanx}

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