Question

एक कमरे की भीतरी लम्बाई चौड़ाई ऊंचाई 5 मीटर , 3 मीटर , 2 मीटर है , यदि प्रत्येक दीवार की मोटाई 20 सेन्टीमीटर हो तो कमरे की चारों दीवारों बाहरी क्षेत्रफल बताओ ?

Answer 1

So the effective length of the room will be = 500+20+20 = 540 cm
Similarly effective width will be 340.
Bit the height will remain same i.e 200cm.

outer surface area of the room = 2(LxH)+2(BxH)
= 2H(L+B) = 2x200x(540+340) = 400x880 = 352000cm² = 35.20m²

Answer 2

Answer:

$719200 cm^2$

Step-by-step explanation:

Inner length of room = 5 m = 500 cm

Inner breadth of room = 3 m = 300 cm

Height of room = 2 m = 200 cm

Thickness = 20 cm

Outer length = 500+20+20=540 cm

Outer breadth = 300+20+20=340 cm

Height will remain same

Outer surface area of the room = $2(L \times H)+2(B \times H) +2(L \times B)$

Outer surface area of the room = $2(540 \times 200)+2(340 \times 200) +2(540 \times 340)$

Outer surface area of the room = $719200 cm^2$

Hence the total outer surface area is $719200 cm^2$