Question

एक कण के कम्पन्न का समीकरण Y = 4 sin(20πt+π/4) द्वारा दिया गया है?​

Answer 1

Answer:

(b) At t = (π/50) s, ys = y1 +y2 = 4[cos(0.4π −30x)− cos(0.4π +3x)]. Using ... ej3π/4 = 2e−jπ/4. A. (e) i(t) = 4sin(ωt +π/3)+3cos(ωt −π/6). = 4cos[π/2−(ωt +π/ 3)] +3cos(ωt −π/6) ... y(x,t) = {40cos(20πt + 20π. 3.

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