) एक मोटार ताशी काही वेगाने 240 किमी धावते. तिचा वेग ताशी 8 किमीने कमी
केल्यास तिला तेवढेच अंतर जाण्यास पूर्वीपेक्षा 1 तास जास्त लागतो तर मोटारीचा
मूळचा ताशी वेग काढा.10th chapter1
Answers
Given :- A motor runs 240 km at some speed per hour. If you reduce its speed by 8 km per hour, it takes 1 hour more to cover the same distance than before, then take the original speed of the car per hour. ?
Solution :-
Let us assume that, original speed of car is x km/h .
so,
→ T1 = D / S = (240/x) hours .
now,
→ New speed = (x - 8) hours .
→ T2 = 240/(x - 8) hours .
A/q,
→ 240/(x - 8) - 240/x = 1
→ 240[(x - x + 8]/(x² - 8x) = 1
→ x² - 8x = 240 * 8
→ x² - 8x - 1920 = 0
→ x² + 40x - 48x - 1920 = 0
→ x(x + 40) - 48(x + 40) = 0
→ (x + 40)(x - 48) = 0
→ x = (-40) or 48 .
since speed cant be in negative.
therefore, the original speed of the car is 48 km/h.
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