Question

एक प्रत्यावर्ती धारा का समीकरण i = 15sin 100πt है। इसकी आवृत्ति ज्ञात
कीजिए।​

Answer 1

Answer:

Frequency of the given AC current is 50 Hz

Explanation:

As we know that the equation of AC current is given as

$i = 15 sin(100\pi t)$

here we know that multiple of time is angular frequency

so we have

$\omega = 100 \pi$

now we know that

$\omega = 2\pi f$

so by comparing above equations we have

$2\pi f = 100 \pi$

$f = 50 Hz$

#Learn

Topic : AC current

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