एक पासे को तीन बार उछाला जाता है तो कम से कम एक बार विषम संख्या प्राप्त होने की प्रायिकता ज्ञात कीजिए।
Answers
Answered by
0
Answer:
7/8
Explanation:
P(atleast one odd) = 1 - P(all even) = 1 - p(even 1st) p(even 2nd)p(even 3rd)= 1 - (3/6)(3/6)(3/6)=1- (1/2)^3= 1-1/8 = 7/8
Answered by
2
Answer:
= 1−1/8=7/8
Hope it helps you
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