Question

एक रेलगाड़ी 360 किलोमीटर की दूरी औसत गति से तय करती है । इसकी गति 5 किलोमीटर प्रति
घंटा अधिक होने पर समान दूरी 48 मिनट कम में तय कर लेती है। इस रेलगाड़ी की मूल गति
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Answer 1

Step-by-step explanation:

A train covers a distance of 360 km at an average speed. If its speed per 5 km/hr is more  the same distance is covered in 48 minutes less. Find the Original speed of this train

• So speed = Distance / Time
• Time = Distance / Speed
•    Distance = 360 km
•     Original Speed = x
•    So Time = 360 / x
• According to Question the speed is increased by 5 km/hr
• Therefore New speed = x + 5
• Also New Time = 360 / x + 5
• We need to convert the time in hours so we get
•           48 / 60
•           4/5
• So equating we get
•     360 / x = 360 / x + 5 + 4/5
•      360 / x – 360 / x + 5 = 4/5
•       360 (1/x – 1/x + 5) = 4/5
•        90 (x + 5 – x / x (x + 5) ) = 4/5
•            x^2 + 5x = 450 x 5
•            x^2 + 5x – 2250 = 0
•            x^2 + 50 x – 45x – 2250 = 0
•            x(x + 50) – 45(x + 50) = 0
•              (x + 50) (x – 45) = 0
•            So x = - 50, 45
• Since speed cannot be negative we get speed = 45 km/.hr

Reference link will be

https://brainly.in/question/12558280