Question

एक संख्या 100 के आधे से कम है 40 से ज्यादा 50 से कम है जिसमें धाय का अंक इकाई के अंक से 2 अधिक है इसके अंको का + 6 है​

Answer 1

Step-by-step explanation:

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Answer 2

Given :-

• Number is less than half of 100 .
• Greater than 40 .
• Tens digit is 2 greater than the unit's digit .
• Sum of digits is 6.

Solution :-

Let us assume that, the required number is (10x + y) .

→ Less than = 100/2 = Less than 50 and greater than 40 .

so,

→ 40 < 10x + y < 50 .

now,

→ x + y = 6

→ x - y = 2

2x = 8

→ x = 4 .

then,

→ y = 6 - 4 = 2 .

therefore,

→ Required number = 10x + y = 10*4 + 2 = 40 + 2 = 42 (Ans.)