Question

एका संख्येच्या 5 पटींमधून वीस वजा
केल्यावर येणारी बाकी ही त्याच संख्येच्या
टीमध्ये 22 मिळवून येणाऱ्या बेरीज एवढी
आहे, आहे तर ती संख्या कोणती?​

Answer 1

Answer:

A solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solutionA solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solutionA solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solutionA solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solutionA solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solutionA solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solution