Question

एक संख्या को क्रमागत 4, 5 तथा 6 से भाग देने पर क्रमश: 2,
3, 4 शेष बचते हैं । वह संख्या है ?​

Answer 1

The required number is 58.

Step-by-step explanation:

Consider the provided information.

First find the LCM of 4, 5 and 6.

4 = 2×2

5 = 5

6 = 2×3

The LCM of 4,5 and 6 is  2×2×3×5=60

Now subtract the difference of divisor and remainder.

4-2=2

5-3=2

6-4=2

So subtract 2 from 60.

60-2=58

Hence, the required number is 58.

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Answer 2

Answer:

answer- 58 which is not sure. .. but keep try i ng your best