Question

एक्स प्लस वन अपऑन 3 माइनस एक्स माइनस एक्स अपॉन टू इक्वल टू एक्स अपऑन 2 ​

Answer 1

SOLUTION

TO DETERMINE

The value of x when

$\displaystyle \sf{ \frac{x + 1}{3} - x - \frac{x}{2} = \frac{x}{2} }$

EVALUATION

$\displaystyle \sf{ \frac{x + 1}{3} - x - \frac{x}{2} = \frac{x}{2} }$

$\displaystyle \sf{ \implies \: \frac{x + 1}{3} = x + \frac{x}{2} + \frac{x}{2} }$

$\displaystyle \sf{ \implies \: \frac{x + 1}{3} = \frac{2x + x + x}{2} }$

$\displaystyle \sf{ \implies \: \frac{x + 1}{3} = \frac{4x}{2} }$

$\displaystyle \sf{ \implies \: \frac{x + 1}{3} = 2x }$

$\displaystyle \sf{ \implies \: 6x = x + 1 }$

$\displaystyle \sf{ \implies \: 6x - x= 1 }$

$\displaystyle \sf{ \implies \: 5 x= 1 }$

$\displaystyle \sf{ \implies \: x= \frac{1}{5} }$

FINAL ANSWER

$\displaystyle \sf{ \: x= \frac{1}{5} }$

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