एक समचतुर्भुज के विकर्ण 25 सेमी तथा 42 सेमी है। इसका क्षेत्रफल एवं परिमाप ज्ञात कीजिए।
Answers
क्षेत्रफल = 525 सेमी ² , परिमाप = 2√2389 सेमी
Step-by-step explanation:
एक समचतुर्भुज के विकर्ण 25 सेमी तथा 42 सेमी है
क्षेत्रफल = (25 * 42)/2 = 525 सेमी ²
भुजा = a
a² = (25/2)² + (42/2)²
=> a² = (1/4) ) (625 + 1764)
=> a² = (1/4) * 289
=> a = (1/2)√2389
परिमाप = 4a = 4 (1/2)√2389 = 2√2389
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Answer:
The Area is 525 square cm.
The Perimeter is 97.76 cm.
Step-by-step explanation:
Area=\frac{1}{2}\times AC\times BD\\
=\frac{1}{2}\times 42\times 25\\
=\frac{1}{2}\times 1050\\
=525 square cm\\
Now we will find the perimeter of the Rhombus.\\
Consider triangle DOC in the given figure,\\
Angle O is 90 degree.
We will apply pythagorean Theorem to evaluate side DC of the triangle.\\
Dc= \sqrt{21^2+12.5^2}
=\sqrt{441+12.5^2}
=\sqrt{441+156.25}
=\sqrt{597.25}
=24.43869 cm.
So, Perimeter=4\cdot \:24.44
=97.76 cm.
