एक समकोण त्रिभुज ABC की एक भुजा BC पर
एक बिन्दु D को चुना गया है, जिसमें AB त्रिभुज
का कर्ण है, तो:
(A) AB^2 +CD^2 = BC^2 +AD^2
(B) CD^2 +BD^2 = 2 AD^2
(C) AB^2 +AC^2 = 2 AD^2
(D) AB^2 = AD^2 + BD^2
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Two lines are given to be parallel. The equation of one of the lines is 4x +3y = 14, = then find the equation of a second line is
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a) Is a right answer ok and follow me
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