Question

एक समकोण त्रिभुज का आधार, संगत ऊँचाई से 10 सेमी. अधिक है। यदि इस त्रिभुज का क्षेत्रफल 600 वर्ग सेमी. है।
भुजाओं का माप ज्ञात कीजिए।
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Answer 1

Height of the triangle will be 30 cm and base will be of 40 cm

Step-by-step explanation:

Let the height of the right angle triangle is x

It is given that base is 10 cm more than the height

So base of the triangle = x+10

We have given area of the right angle triangle is 600 $m^2$

We know that area of right angle triangle is given by $A=\frac{1}{2}\times base\times height$

So $600=\frac{1}{2}\times x\times (x+10)$

$x^2+10x=1200$

$x^2+10x-1200=0$

$x^2+40x-30x-1200=0$

$x(x+40)-30(x+40)=0$

$(x+40)(x-30)=0$

x = -40 and x = 30

As side of the right angle triangle can not be negative so x = 30

So length of height is 30 cm

And length of base = x+10 = 30+10 = 40 cm

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