एक्सटीरियर एंगल ऑफ द सेम sideऑफ़ द transversal ऑफ parallel lines measures[ x+15°] and (3x+5°) find the angle
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Answer:
(x+15°) + (3x +5°) = 180°
x+15°+3x+5° = 180°
4x + 20° = 180°
4x = 180°-20°
4x = 160°
x = 160°/4
x = 40°
First angle = x+15° = 40°+15° =55°
Second angle = 3x+5° = 3×40°+5° = 120+5°
= 125°
So, Answer is 55°,125°
I hope this is helpful to you.........
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