Question

एक्सटीरियर एंगल ऑफ द सेम sideऑफ़ द transversal ऑफ parallel lines measures[ x+15°] and (3x+5°) find the angle​

Answer 1

Answer:

(x+15°) + (3x +5°) = 180°

x+15°+3x+5° = 180°

4x + 20° = 180°

4x = 180°-20°

4x = 160°

x = 160°/4

x = 40°

First angle = x+15° = 40°+15° =55°

Second angle = 3x+5° = 3×40°+5° = 120+5°

= 125°

So, Answer is 55°,125°

I hope this is helpful to you.........