Question

एक शादी समारोह में 2200 से 2600 के बीच अतिथि
आमंत्रित किए गए। समारोह प्रबंधक ने यह तय किया कि
वह बैठने की व्यवस्था इस प्रकार करेगी कि प्रत्येक मेज पर
बराबर संख्या में अतिथि बैंठेगे और प्रत्येक मेज पर
अतिथियों की संख्या एक विषम संख्या होगी। उसने गणना
की और पाया कि प्रत्येक मेज पर तीन अतिथि बैठाने पर
दो अतिथि बच जाएंगे, प्रत्येक मेज पर पाँच अतिथि बैठाने
पर चार अतिथि बच जाएंगे, प्रत्येक मेज पर सात अतिथि
बैठाने पर छह अतिथि बच जाएंगे और प्रत्येक मेज पर नौ
अतिथि बैठाने पर आठ अतिथि बच जाएंगे। हालांकि, जब
उसने प्रत्येक मेज पर 11 अतिथि बैठाने का प्रयास किया
तो सभी मेजों पर बराबर अतिथि बैठ गए और कोई अतिथि
नहीं बचा। तो समारोह में कुल कितने अतिथि आमंत्रित
किए गए?
Plzzz translate it in English ​

Answer 1

Answer:

Guest between 2200 and 2600 in a wedding ceremony  Were invited The ceremony manager decided that  ,She will arrange the seating in such a way that on every table  An equal number of guests will sit at each table  . The number of guests will be an odd number. He calculated  ,And found that three guests at each table ,Two guests will be saved, seating five guests at each table  ,But four guests will be saved, seven guests at each table

Six guests will be saved by seating and nine on each table   Eight guests will be saved on guest seating. However, when  He tried to seat 11 guests at each table  So equal guests sat on all the tables and any guest   Not left So how many guests were invited to the ceremony   were done?

to find = number of guest between 2200 and 2600  

solution  = divide 3,5.7.and 9 it gives 2,4,6 and 8 . when we divide by 11 it is completely divisible.  

(3-2) = (5-4) = (7-6) = (9-8) = 1 ...(from the above numbers )

find L.C.M of 3,5,7 and 9.

3= 3X1=3  

5= 5X1=5

7= 7X1=7

9= 9X3=9

L.C.M  = 3 X 3 5 X 7 =315  

LCM - 1 = 315 -1 = 314  

Accorning to condition mentioned In question,  

number must divisible by 11 so,

IF,  

X = 2 = 315 X 2 -1 / 11 = 629 /11 = 2 (Remainder )  

X = 3 = 315 X 3 -1 = 944/11 = 9

X = 4 = 315 X 4 -1 = 1574 / 11= 5

X = 5 315 X 5-1 = 1574 / 11= 1  

X = |

      |

      |

If X = 8 = 315 X 8 -1 / 11 = 0  

so the final answer is 2519 which is greater than 2200 and also small than 2600.