Physics, asked by sk2631261, 1 year ago

एक ताकतवर स्वस्थ व्यक्ति 11.8 मी. ऊँचे भवन से 7 मी.दूरी पर खड़ा है,वह देखता है कि ऊपरी मंजिल से एक बच्चा फिसलकर गिर गया है।बच्चे को अपनी बाँहों (ऊँचाई 1.8)झेलने के लिए उसे किस चाल(एकसमान माने)से भागना चाहिए।

Answers

Answered by anvi61

Please translate all this in English language because I am student of a English Medium school (I know Hindu but I can't reply it in Hindi

sk2631261: A mighty healthy man stands at 7 km away from 11.8m tall buildings.He sees that a child slipped from the upper floors.His arms height is1.8m. What uniform speed should he keep to catch the child at that time?

sk2631261: U can give me ans in English or Hindi.

anvi61: English

sk2631261: Ok

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