एक तीन अंकी संख्या तिच्या अंकांच्या बेरजेच्या सतरापट आहे.अंकांची अदलाबदल केल्यावर मिळणारी संख्या मूळ संख्येपेक्षा 198 ने मोठी आहे. टोकाच्या अंकांची बेरीज मधल्या अंकापेक्षा 1 ने लहान आहे.तर मूळ संख्या शोधा."
Answers
मूळ संख्या = 153
Step-by-step explanation:
A three-digit number is 17 times the sum of its digits. The number obtained after the exchange of digits is 198 larger than the original number. Find the original number
Number ABC
100A + 10B + C = 17 (A + B + C)
=> 83A = 7B + 16C
The number obtained after the exchange of digits
CBA
100C + 10B + A = 198 + 100A + 10B + C
=> 99C = 99A + 198
=> C = A + 2
=> 83A = 7B + 16(A + 2)
=> 67A = 7B + 32
A = 1 , B = 5
C = 3
153
संख्या ABC
100A + 10B + C = 17 (A + B + C)
=> 83A = 7 B+ 16 C
अंकांच्या देवाणघेवाणानंतर प्राप्त केलेली संख्या
CBA
100 C + 10 B+ A = 198 + 100 A + 10 B + C
=> 99 C = 99 A + 198
=> C = A + 2
=> 83 A = 7 B + 16 (A + 2)
=> 67 A = 7 B + 32
A = 1, B = 5
C = 3
153
मूळ संख्या = 153
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