Question

एक त्रिभुज ABC की रचना कीजिए जिसमें BC=3.6cm AB+AC=4.8 ओर B=60'​

Answer 1

Explanation:

1. Draw a line segment BC of 3.6cm.

2. At the point B, draw ∠x BC of 60o

3. With center B and radius 4.8cm, draw an arc which intersects XB at D.

4. Join DC

5. Draw the perpendicular bisector of DC which intersects DB at A.

6. Join AC Hence Δ ABCis the required triangle.