Question

एक त्रिभुज ABC की रचना कीजिए जिसमें ZB=60
LC=45तथा AB+BC+CA=11सेमी हो।​

Answer 1

Given  :  AB+BC+CA=11 सेमी   ,  ∠B = 60° & ∠C = 45°  

To Find :  त्रिभुज ABC की रचना कीजिए . Construct triangle

Solution:

Step 1 : Draw  a line segment XY  = 11 cm

Step 2 : Make an angle of 60 ° at X on XY using protector

Step 3 : Make an angle of 45° at Y on XY using protector

Step 4 : Draw angle bisector of 60°  & 45° and let them intersect at A

Step 5 : Draw perpendicular bisector of AX  & AY and let them intersect XY at B  & C

ΔABC is required triangle

∠B = 60° & ∠C = 45° and AB+BC+CA = 11 cm

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