Question

एक त्रिभुजाकार खेत की भुजाएं क्रमशः 20 मी,21 मी , 29 मी है इस खेत में रु 4.50प्रतिवर्ग मी की दर से फसल काटने का व्यय होगा​

Answer 1

Step-by-step explanation:

Let the sides of the triangular field be a, b and c metres.

Therefore, a = 20 m, b 21 m and c = 29 m.

Now, Semi Perimeter

$s = \frac{a + b + c}{2} \\ = \frac{20 + 21 + 29}{2} \\ = \frac{70}{2} = 35 \: m \\ s - a = 35 - 20 = 15 \\ s - b = 35 - 21 = 14 \\ s - c = 35 - 29 = 6 \\ \\ area \: of \: field \\ = \sqrt{s( s - a)(s - b)(s - c )} \\ = \sqrt{35 \times 15 \times 14 \times 6} \\ = \sqrt{7 \times 5 \times 3 \times 5 \times 7 \times 2 \times 3 \times 2} \\ = \sqrt{7 \times 7 \times 5 \times 5 \times 3 \times 3 \times 2 \times 2} \\ = 7 \times 5 \times 3 \times 2 \\ = 210 \: sq \: m \\ cost \: of \: harvesting \\ = 210 \times 4.50 \\ = Rs. \: 945$