Hindi, asked by jaykrishnaengworks, 16 days ago

एक तलाब 40 मीटर गहराई से 10 c तापमान पर रहता है 1 सेंटीमीटर बायसन का एक हवा का बुलबुला ऊपर की ओर आता है जब वह सतह पर पहुंचता है तब उसका तापमान 30 डिग्री सेल्सियस हो जाता है उसका आयतन कितना होता है

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Answers

Answered by dndjekajsndn
0

Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. ... Forces only exist as a result of an interaction.

Explanation:

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. ... Forces only exist as a result of an interaction.

Answered by knjroopa
0

Explanation:

A pond 40 meters deep remains at a temperature of 10 C An air bubble of 1 cm cube comes upwards when it reaches the surface then its temperature becomes 30 ° C What is its volume  

  • Volume of air bubble V1 = 1 cm^3 = 1 x 10^-6 m^3
  • A pond depth will be d = 40 m
  • Temperature at the depth will be T1 = 10 degree C = 273 + 10 = 283 K
  • Temperature at the surface of the pond T2 = T2 = 30 degree C = 273 + 30 = 303 K
  • Pressure on the surface of the pond P2 = 1 atm = 1 x 1.013 x 10^5 Pa
  • Now P1 = 1 atm + ρgh
  • ρ = 10^3 kg/m^3
  • g = 9.8 m/s
  • So P1 = 1.013 x 10^5 + 40 x 10^3 x 9.8
  •          = 493300 Pa
  • We have P1V1 /T1 = P2V2 /T2
  • Now volume of air bubble when it reaches the surface will be
  •                   V2 = P1V1T2 / T1P2
  •                       = 493300 x 1 x 10^-6 x 303 / 283 x 1.013 x 10^5
  •                        = 149469900 x 10^-6 /286.679 x 10^5
  •                           = 5.213 x 10^-6 m^3
  •                          = 5.213 cm^3  

Reference link will be

https://brainly.in/question/9966999

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