Question

एक तत्व X का परमाणु द्रव्यमान 16.2 u है तो इसके किसी एक नमूने
समस्थानिक 16 और 18x का प्रतिशत क्या होगा​

Answer 1

Answer:

X=10%,90%

Explanation:

16.2=18x+16(100-x)/100

1620=18x+1600-16x

2x=20

X=10%,90%

Answer 2

Isotopic abundance of 16 u is 90% and that of 18 u is 10%

Explanation:

Mass of isotope 1 = 16 u

% abundance of isotope 1 = x% = $\frac{x}{100}$

Mass of isotope 2 = 18 u

% abundance of isotope 2 = (100-x) % = $\frac{100-x}{100}$

Formula used for average atomic mass of an element

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$16.2=[(16\times \frac{x}{100})+(18\times \frac{100-x}{100})]$

$x=90$

(100-x) = (100-90)= 10

Thus isotopic abundance of 16 u is 90% and that of 18 u is 10%

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