Math, asked by sid6963, 10 months ago

| एक दुकानदार 520 रू. में दो वस्तुएँ खरीदता है। एक वस्तु को
वह 16% लाभ और दूसरी को 10% हानि के साथ बेचता है,
जिससे उसे इस लेन देन में न लाभ होता है और न ही हानि ।
| होती है। हानि पर बेची गई वस्तु का विक्रय मूल्य क्या होगा ?​

Answers

Answered by bhabesh56
7

Answer:

520/100×16=83.2

520/100×10=52

83.2-52=31.2

Answered by slicergiza
0

Answer:

320 rupees

Step-by-step explanation:

Given,

The total cost price = 520 rupees,

Let the cost price of the first article = x rupees,

So, the cost price of the second article = ( 520 - x ) rupees,

If there is a profit of 16% in the first article,

Then the selling price of first article = x + 16% of x

= x + 0.16x

= 1.16x

Now, there is a loss of 10% in the second article,

Then the selling price of the second article = (520-x) - 10%(520-x)

= (520-x) - 0.1(520-x)

= 520 - x - 52 + 0.1x

= 468 - 0.9x

Thus, the total selling price of both article = 1.16x + 468 - 0.9x = 468 + 0.26x

According to the question,

There is no loss and no profit in both item,

∴ Selling price of both article = 520 rupees,

468 + 0.26x = 520

0.26x = 52

x = 200

Hence, the cost price of second article = 520 - 200 = 320 rupees.

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