Question

एक द्विघात बहुपद ज्ञात कीजिए, जिसके मूलों का योग -5 तथा गुणनफल 6 है। यहाँ बहुपद के मूल को ज्ञात कीजिए।​

Answer 1

Answer:

x=-3,-2

Step-by-step explanation:

use formula

x squere-( mul ka yog)x+mul ka gunofl

x squere-(-5)x+6

x squere+5x+6

xsquere+2x+3x+6

x(x+2)+3(x+2)

(x+3)(x+2)

x=-3,-3

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Answer 2

$\sf\ your \: ans = - 3 \: and \: - 2$

$\bf\ the \: general \: form \: of \: quadratic \: equtation \: is\\ \\ \sf\ \implies {x}^{2} - (sum \: of \:the \: roots) + (product \: of \: the \: roots) = 0 \\ \\ \bf\ here \: \\ \sf\ \: sum \: of \: roots = - 5 \\ \sf\ product \: of \: roots = 6 \\ \\ \sf\ \: \underline{now \: the \: values \: put \: in \: the \: {eq}^{ \bf \: n} \: we \: get } \\ \\ \bf\ {x}^{2} - ( - 5)x + 6 = 0 \\ \\ \sf\ \implies: {x}^{2} + 5x + 6 = 0 \\ \\ \sf\ \implies: {x}^{2} + (2x + 3x) + 6 =0 \\ \\ \sf\ \implies: {x}^{2} + 2x + 3x + 6 = 0 \\ \\ \sf\ \implies: x(x + 2) + 3(x + 2) = 0 \\ \\ \boxed{\sf\ \implies: (x + 2)(x + 3) = 0} \\ \\ \huge \frac{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{} \\ \\ \bf\ x + 2 = 0 \\ \\ \boxed{\sf\ \implies: x = - 2 }\\ \\ \sf\ x + 3 = 0 \\ \\ \boxed{\sf\ \implies: x = - 3 } \\ \\ \bf\ \underline{so \: the \: roots \: of \: the \: equtation = - 2 \: and - 3}$