Question

एक उत्तल लेंस की फोकस दूरी 40 सेंटीमीटर है लेंस की क्षमता की गणना कीजिए​

Answer 1

Explanation:

p =1/f(m)

given, f= 40cm = 100/40m

p= 40/100

p= 0.40

Answer 2

Answer:

Power of lense = 1/f

Where f is in meter.

$p \: = \frac{1}{f} = \frac{1}{0.40} = 2.5 \: diopter$