Question

एक विद्यार्थी दस 2 अंकिया संख्या का औसत ज्ञात करता है संख्या की नकल करते समय वो गलती से एक संख्या को उसके परस्पर बदलते हुए अंको वाली संख्या लिख लेता है परिणाम स्वरूप उसका उत्तर सही उत्तर से 1.8 कम आता है जिस संख्या को लिखने में उसने गलती कि थी उसके अंको का अंतर क्या होगा?

Answer 1

Answer:

A student finds the average of ten 2-digit numbers, while copying the number, he mistakenly writes a number with its interchanging number, as a result his answer is 1.8 less than the correct answer. What was the difference between his pointsA student finds the average of ten 2-digit numbers, while copying the number, he mistakenly writes a number with its interchanging number, as a result his answer is 1.8 less than the correct answer. What was the difference between his points

Explanation:

Answer 2

उतर :-

माना दस 2-अंकीय संख्याएं है :- (10x₁ + y₁) , (10x₂ + y₂) __________ (10x₁₀ + y₁₀) .

अत,

→ औसत = सभी संख्याओं का जोड़ / कुल संख्याएं

→ औसत = (10x₁ + y₁) + (10x₂ + y₂) + __________ + (10x₁₀ + y₁₀) / 10

→ औसत = [10(x₁ + x₂ + ____ x₁₀) + (y₁ + y₂ + ___ y₁₀)]/10 --------------- (1)

अब माना विद्यार्थी ने (10x₁ + y₁) को गलती से (10y₁ + x₁) लिख दिया l

तब,

→ नया औसत = (10y₁ + x₁) + (10x₂ + y₂) + __________ + (10x₁₀ + y₁₀) / 10

→ नया औसत = [10(y₁ + x₂ + ____ x₁₀) + (x₁ + y₂ + ___ y₁₀)]/10 --------------- (1)

दिया हुआ है कि, उसका उत्तर सही उत्तर से 1.8 कम आता है ।

अत,

→ (1) - (2) = 1.8

→ [10(x₁ + x₂ + ____ x₁₀) + (y₁ + y₂ + ___ y₁₀)] - [10(y₁ + x₂ + ____ x₁₀) + (x₁ + y₂ + ___ y₁₀)] = 1.8 * 10

→ 10(x₁ - y₁ + x₂ - y₂ _____ x₁₀ - x₁₀) + (y₁ - x₁ + y₂ - y₂ ___ y₁₀ - y₁₀) = 18

→ 10(x₁ - y₁) + (y₁ - x₁) = 18

→ 10x₁ - x₁ + y₁ - 10y₁ = 18

→ 9x₁ - 9y₁ = 18

→ 9(x₁ - y₁) = 18

→ (x₁ - y₁) = 2 (Ans.)

इसलिए जिस संख्या को लिखने में उसने गलती की थी, उसके अंकों का अन्तर 2 होगा ll

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