एक व्यक्ति अपनी पत्नी से 4 वर्ष बड़ा है उसकी पत्नी अपनी पुत्री से 10 गुना बड़ी है उसकी पुत्री 2 वर्ष बाद 6 वर्ष की होगी तो व्यक्ति की वर्तमान आयु क्या है
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let the age of the daughter be- x
then the age of the wife becomes- 10x
the age of the person becomes- 10x+4
after 2 years
the age of the girl is x+2 which is equal to 6
then x is 6-2 is 4
hence the age of the person is 10(4) + 4 equal to 44 years
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