Question

eku is older than her brother by 4 years. Tweleve years ago,the ratio of their age was 3:5.find their present age.​

Answer 1

Step-by-step explanation:

Given:-

Eku is older than her brother by 4 years. Tweleve years ago,the ratio of their age was 3:5

To Find:-

Eku and her brother's present age

Solution:

Let Eku's brother present age be x years

Eku's present age=x+4 years

Twelve years ago,

Eku's brother's age was=x-12 years

Eku's present age =x+4-12=x-8 years

ACQ

$\therefore \: \tt \bigg( \frac{x - 12}{x - 8} \bigg) = \frac{3}{5} \\ \bigg [ \sf \: by \: cross \: multiplying \: we \: get \bigg] \\ \tt \dashrightarrow \: 5(x - 12) =3(x - 8) \\ \tt \dashrightarrow5x - 60 = 3x - 24 \\ \tt \dashrightarrow \: 5x - 3x = ( - 24) + 60 \\ \tt \dashrightarrow2x = 36 \\ \tt \dashrightarrow \: x = \frac{36}{2} \\ \tt \dashrightarrow \: x = \frac{ \cancel{36}}{ \cancel{2}} </p><p> \\ \tt \dashrightarrow \green{ \boxed{ \underline{ \red{18}}}}</p><p>$

Present age of Eku's brother=18 years

Present age of Eku's=x+4=18+4=22 years

Answer 2

Let Eku's brother present age be x years

Eku's present age = x +4 years

• Twelve years ago,

Eku's brother's age was=x-12 years

Eku's present age = x+4-12 = x-8 years

ATQ -

$\begin{gathered} \therefore \: \tt \bigg( \frac{x - 12}{x - 8} \bigg) = \frac{3}{5} \\ \bigg [ \sf \: by \: cross \: multiplying \: we \: get \bigg] \\ \tt \dashrightarrow \: 5(x - 12) =3(x - 8) \\ \tt \dashrightarrow5x - 60 = 3x - 24 \\ \tt \dashrightarrow \: 5x - 3x = ( - 24) + 60 \\ \tt \dashrightarrow2x = 36 \\ \tt \dashrightarrow \: x = \frac{36}{2} \\ \tt \dashrightarrow \: x = \frac{ \cancel{36}}{ \cancel{2}} \\ \tt \dashrightarrow \orange{ \boxed{ \underline{ \purple{18}}}} \end{gathered}$

by cross multiply in

weget

⇢5(x−12) = 3(x−8)

⇢5x−60 = 3x−24

⇢5x−3x = ( −24)+60

⇢2x = 36

⇢x = 36/2

⇢x = 16

Present age of Eku's brother=18 years

Present age of Eku's=x+4=18+4=22 years