Question

एल एम एन ओ एस ए क्वॉड्रिलैटरल ओए मेल्स इक्वल टू 45 डिग्री फाइंड एक्स वाई जेड​

Answer 1

Step-by-step explanation:

Both pairs of adjacent sides of a kite are equal, therefore,

AB=AD and BC=CD

In ΔABD,∠ABD=∠ADB=40

∘

(isos. Δ property)

Since the diagonals of a kite intersect at rt. ∠s,∠AOB=90

∘

.

In ΔAOB,x=∠OAB=180

∘

−(90

∘

+40

∘

)

=180

∘

−130

∘

=50

∘

In ΔBOC,y=∠OBC=180

∘

−(90

∘

+32

∘

)

=180

∘

−122

∘

=58

∘

Diagonals of kite bisect the angles at the vertices

z=32

∘

hope it helps yoi