Election configuration of nitrogen is 1s2 2s2 sp3 imagine if their I'd only 2orbitals (Px,Py) now write the electronic configuration in this imaginary condition
dastagiri:
Show according to hunds rule
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1s2 2s2 2px2 2py1 is config.
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1s2 2s2 2p3. Reason is if in p subshell only px and py are present then it can accommodate 4 electrons. So the imaginary condition will be same as the previous one.
Show according to hunds rule
i have did it buddy
Yaa...i expected the same but didn't present it there. According to hunds rule every orbital in a subshell is singly occupied with one electron before any one orbital is doubly occupied, and all electrons in singly occupied orbitals have the same spin. so the imaginary condition would be 1s2 2s2 2px2 2py1
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