Question

Electric bulb 3 volt drawn, a current of 1 ampere is a bulb is on for 5 month calculate energy released month

Answer 1

V = 3 V ; I = 1 A ;

t = 5 month = 5×30 = 150 days

= 150×24 h

As , Q = V I t

so, energy released = 3×1×150×24 Wh

= 450×24 Wh = 10800 Wh = 10.8 kWh