Electric bulb 3 volt drawn, a current of 1 ampere is a bulb is on for 5 month calculate energy released month
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V = 3 V ; I = 1 A ;
t = 5 month = 5×30 = 150 days
= 150×24 h
As , Q = V I t
so, energy released = 3×1×150×24 Wh
= 450×24 Wh = 10800 Wh = 10.8 kWh
t = 5 month = 5×30 = 150 days
= 150×24 h
As , Q = V I t
so, energy released = 3×1×150×24 Wh
= 450×24 Wh = 10800 Wh = 10.8 kWh
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